19x^2-2x-17=0

Solution for 19x^2-2x-17=0 equation:

19x^2-2x-17=0

a = 19; b = -2; c = -17;
Δ = b2-4ac
Δ = -22-4·19·(-17)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-36}{2*19}=\frac{-34}{38}
=-17/19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+36}{2*19}=\frac{38}{38}
=1
$